Base | Representation |
---|---|
bin | 11001010101011101… |
… | …11101011001110101 |
3 | 1022002221021211102212 |
4 | 30222232331121311 |
5 | 210324033330333 |
6 | 10125410543205 |
7 | 661031601131 |
oct | 145256753165 |
9 | 38087254385 |
10 | 13601855093 |
11 | 584a990062 |
12 | 2777297b05 |
13 | 1389c99a88 |
14 | 9306763c1 |
15 | 5491d9448 |
hex | 32abbd675 |
13601855093 has 2 divisors, whose sum is σ = 13601855094. Its totient is φ = 13601855092.
The previous prime is 13601855081. The next prime is 13601855101. The reversal of 13601855093 is 39055810631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13418442244 + 183412849 = 115838^2 + 13543^2 .
It is a cyclic number.
It is not a de Polignac number, because 13601855093 - 24 = 13601855077 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13601855093.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13601855053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6800927546 + 6800927547.
It is an arithmetic number, because the mean of its divisors is an integer number (6800927547).
Almost surely, 213601855093 is an apocalyptic number.
It is an amenable number.
13601855093 is a deficient number, since it is larger than the sum of its proper divisors (1).
13601855093 is an equidigital number, since it uses as much as digits as its factorization.
13601855093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 13601855093 in words is "thirteen billion, six hundred one million, eight hundred fifty-five thousand, ninety-three".
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