13604043301 has 4 divisors (see below), whose sum is σ = 14320045600. Its totient is φ = 12888041004.

The previous prime is 13604043269. The next prime is 13604043311. The reversal of 13604043301 is 10334040631.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13604043301 - 2⁵ = 13604043269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13604043311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358001121 + ... + 358001158.

It is an arithmetic number, because the mean of its divisors is an integer number (3580011400).

Almost surely, 2^13604043301 is an apocalyptic number.

It is an amenable number.

13604043301 is a deficient number, since it is larger than the sum of its proper divisors (716002299).

13604043301 is an equidigital number, since it uses as much as digits as its factorization.

13604043301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 716002298.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13604043301 its reverse (10334040631), we get a palindrome (23938083932).

The spelling of 13604043301 in words is "thirteen billion, six hundred four million, forty-three thousand, three hundred one".