Base | Representation |
---|---|
bin | 111111010110101001… |
… | …0111010100010110011 |
3 | 111000011122201100212022 |
4 | 1332231102322202303 |
5 | 4212113124343211 |
6 | 142300125422055 |
7 | 12554323562333 |
oct | 1765522724263 |
9 | 430148640768 |
10 | 136051402931 |
11 | 52776519784 |
12 | 2244b40a92b |
13 | caa27ca422 |
14 | 68290590c3 |
15 | 3814251bdb |
hex | 1fad4ba8b3 |
136051402931 has 2 divisors, whose sum is σ = 136051402932. Its totient is φ = 136051402930.
The previous prime is 136051402919. The next prime is 136051402933. The reversal of 136051402931 is 139204150631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136051402931 - 210 = 136051401907 is a prime.
It is a super-2 number, since 2×1360514029312 (a number of 23 digits) contains 22 as substring.
Together with 136051402933, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 136051402891 and 136051402900.
It is not a weakly prime, because it can be changed into another prime (136051402933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68025701465 + 68025701466.
It is an arithmetic number, because the mean of its divisors is an integer number (68025701466).
Almost surely, 2136051402931 is an apocalyptic number.
136051402931 is a deficient number, since it is larger than the sum of its proper divisors (1).
136051402931 is an equidigital number, since it uses as much as digits as its factorization.
136051402931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 136051402931 in words is "one hundred thirty-six billion, fifty-one million, four hundred two thousand, nine hundred thirty-one".
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