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136052223009541 is a prime number
BaseRepresentation
bin11110111011110100100000…
…011011000110001100000101
3122211201110120100100121002121
4132323310200123012030011
5120313034423042301131
61201205310045205541
740441306626400036
oct3673644033061405
9584643510317077
10136052223009541
113a3944730186a3
12133139ba2608b1
135abb8920b1557
142584d69a28a8d
1510ae06d13a911
hex7bbd206c6305

136052223009541 has 2 divisors, whose sum is σ = 136052223009542. Its totient is φ = 136052223009540.

The previous prime is 136052223009343. The next prime is 136052223009569. The reversal of 136052223009541 is 145900322250631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103836711400900 + 32215511608641 = 10190030^2 + 5675871^2 .

It is a cyclic number.

It is not a de Polignac number, because 136052223009541 - 231 = 136050075525893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136052223019541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68026111504770 + 68026111504771.

It is an arithmetic number, because the mean of its divisors is an integer number (68026111504771).

Almost surely, 2136052223009541 is an apocalyptic number.

It is an amenable number.

136052223009541 is a deficient number, since it is larger than the sum of its proper divisors (1).

136052223009541 is an equidigital number, since it uses as much as digits as its factorization.

136052223009541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 136052223009541 in words is "one hundred thirty-six trillion, fifty-two billion, two hundred twenty-three million, nine thousand, five hundred forty-one".