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1360720114213 is a prime number
BaseRepresentation
bin10011110011010001001…
…111010011001000100101
311211002020220221211222011
4103303101033103020211
5134243223322123323
62521034534234221
7200210625063415
oct23632117231045
94732226854864
101360720114213
11485095037769
1219b8724b5971
139b413ab70c5
1449c05930645
15255de9c020d
hex13cd13d3225

1360720114213 has 2 divisors, whose sum is σ = 1360720114214. Its totient is φ = 1360720114212.

The previous prime is 1360720114189. The next prime is 1360720114219. The reversal of 1360720114213 is 3124110270631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1015707199329 + 345012914884 = 1007823^2 + 587378^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1360720114213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1360720114219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680360057106 + 680360057107.

It is an arithmetic number, because the mean of its divisors is an integer number (680360057107).

Almost surely, 21360720114213 is an apocalyptic number.

It is an amenable number.

1360720114213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360720114213 is an equidigital number, since it uses as much as digits as its factorization.

1360720114213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1360720114213 its reverse (3124110270631), we get a palindrome (4484830384844).

The spelling of 1360720114213 in words is "one trillion, three hundred sixty billion, seven hundred twenty million, one hundred fourteen thousand, two hundred thirteen".