Base | Representation |
---|---|
bin | 1100011000001100000110… |
… | …0111101010111110110111 |
3 | 1210012002000201122022020211 |
4 | 3012003001213222332313 |
5 | 3240440133411433322 |
6 | 44540113450210251 |
7 | 2603161113015511 |
oct | 306030147527667 |
9 | 53162021568224 |
10 | 13609704796087 |
11 | 437793060a224 |
12 | 163979a723987 |
13 | 77950b0c42ca |
14 | 3509db146bb1 |
15 | 1890464eeb77 |
hex | c60c19eafb7 |
13609704796087 has 2 divisors, whose sum is σ = 13609704796088. Its totient is φ = 13609704796086.
The previous prime is 13609704796033. The next prime is 13609704796091. The reversal of 13609704796087 is 78069740790631.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13609704796087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13609704796027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6804852398043 + 6804852398044.
It is an arithmetic number, because the mean of its divisors is an integer number (6804852398044).
Almost surely, 213609704796087 is an apocalyptic number.
13609704796087 is a deficient number, since it is larger than the sum of its proper divisors (1).
13609704796087 is an equidigital number, since it uses as much as digits as its factorization.
13609704796087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96018048, while the sum is 67.
The spelling of 13609704796087 in words is "thirteen trillion, six hundred nine billion, seven hundred four million, seven hundred ninety-six thousand, eighty-seven".
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