Base | Representation |
---|---|
bin | 10011110011100101100… |
… | …001111110010100101111 |
3 | 11211010010122112222121022 |
4 | 103303211201332110233 |
5 | 134244423000212111 |
6 | 2521132415124355 |
7 | 200222230552343 |
oct | 23634541762457 |
9 | 4733118488538 |
10 | 1361060554031 |
11 | 48524a222192 |
12 | 19b9485136bb |
13 | 9b4694a3999 |
14 | 49c38c2d623 |
15 | 2560e81b2db |
hex | 13ce587e52f |
1361060554031 has 2 divisors, whose sum is σ = 1361060554032. Its totient is φ = 1361060554030.
The previous prime is 1361060553997. The next prime is 1361060554043. The reversal of 1361060554031 is 1304550601631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361060554031 - 26 = 1361060553967 is a prime.
It is a super-2 number, since 2×13610605540312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1361060553982 and 1361060554000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361060554631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680530277015 + 680530277016.
It is an arithmetic number, because the mean of its divisors is an integer number (680530277016).
Almost surely, 21361060554031 is an apocalyptic number.
1361060554031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361060554031 is an equidigital number, since it uses as much as digits as its factorization.
1361060554031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 1361060554031 in words is "one trillion, three hundred sixty-one billion, sixty million, five hundred fifty-four thousand, thirty-one".
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