Base | Representation |
---|---|
bin | 11110111100101011010001… |
… | …000001011000100110101011 |
3 | 122211221002100001001002012111 |
4 | 132330223101001120212223 |
5 | 120320020332211130212 |
6 | 1201252312313423151 |
7 | 40445460654145324 |
oct | 3674532101304653 |
9 | 584832301032174 |
10 | 136111020411307 |
11 | 3a4073a5684917 |
12 | 1332328940aab7 |
13 | 5ac42a2647746 |
14 | 2587b468b344b |
15 | 10b085eedcea7 |
hex | 7bcad10589ab |
136111020411307 has 2 divisors, whose sum is σ = 136111020411308. Its totient is φ = 136111020411306.
The previous prime is 136111020411287. The next prime is 136111020411313. The reversal of 136111020411307 is 703114020111631.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136111020411307 is a prime.
It is not a weakly prime, because it can be changed into another prime (136111021411307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68055510205653 + 68055510205654.
It is an arithmetic number, because the mean of its divisors is an integer number (68055510205654).
Almost surely, 2136111020411307 is an apocalyptic number.
136111020411307 is a deficient number, since it is larger than the sum of its proper divisors (1).
136111020411307 is an equidigital number, since it uses as much as digits as its factorization.
136111020411307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 31.
Adding to 136111020411307 its reverse (703114020111631), we get a palindrome (839225040522938).
The spelling of 136111020411307 in words is "one hundred thirty-six trillion, one hundred eleven billion, twenty million, four hundred eleven thousand, three hundred seven".
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