Base | Representation |
---|---|
bin | 11001010110100100… |
… | …10101111010100011 |
3 | 1022010120202001221121 |
4 | 30223102111322203 |
5 | 210333422134111 |
6 | 10130341433111 |
7 | 661203462205 |
oct | 145322257243 |
9 | 38116661847 |
10 | 13611130531 |
11 | 5855145909 |
12 | 277a40b797 |
13 | 138bb968bb |
14 | 9319ac775 |
15 | 549e1c871 |
hex | 32b495ea3 |
13611130531 has 2 divisors, whose sum is σ = 13611130532. Its totient is φ = 13611130530.
The previous prime is 13611130469. The next prime is 13611130549. The reversal of 13611130531 is 13503111631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13611130531 - 221 = 13609033379 is a prime.
It is a super-2 number, since 2×136111305312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13611130496 and 13611130505.
It is not a weakly prime, because it can be changed into another prime (13611130571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6805565265 + 6805565266.
It is an arithmetic number, because the mean of its divisors is an integer number (6805565266).
Almost surely, 213611130531 is an apocalyptic number.
13611130531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13611130531 is an equidigital number, since it uses as much as digits as its factorization.
13611130531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
The spelling of 13611130531 in words is "thirteen billion, six hundred eleven million, one hundred thirty thousand, five hundred thirty-one".
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