Base | Representation |
---|---|
bin | 1100011000010011101111… |
… | …1001000000110001000001 |
3 | 1210012021022200122111102022 |
4 | 3012010323321000301001 |
5 | 3241003334034141423 |
6 | 44541053210131225 |
7 | 2603263002234464 |
oct | 306047371006101 |
9 | 53167280574368 |
10 | 13611756162113 |
11 | 437879354a94a |
12 | 163a071720b15 |
13 | 7797770b4765 |
14 | 350b537732db |
15 | 18911665bdc8 |
hex | c613be40c41 |
13611756162113 has 2 divisors, whose sum is σ = 13611756162114. Its totient is φ = 13611756162112.
The previous prime is 13611756162001. The next prime is 13611756162157. The reversal of 13611756162113 is 31126165711631.
It is an a-pointer prime, because the next prime (13611756162157) can be obtained adding 13611756162113 to its sum of digits (44).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13602767605249 + 8988556864 = 3688193^2 + 94808^2 .
It is a cyclic number.
It is not a de Polignac number, because 13611756162113 - 216 = 13611756096577 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (13611756462113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6805878081056 + 6805878081057.
It is an arithmetic number, because the mean of its divisors is an integer number (6805878081057).
Almost surely, 213611756162113 is an apocalyptic number.
It is an amenable number.
13611756162113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13611756162113 is an equidigital number, since it uses as much as digits as its factorization.
13611756162113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 136080, while the sum is 44.
The spelling of 13611756162113 in words is "thirteen trillion, six hundred eleven billion, seven hundred fifty-six million, one hundred sixty-two thousand, one hundred thirteen".
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