Base | Representation |
---|---|
bin | 10011110011101110101… |
… | …101111101001101110011 |
3 | 11211010112101120220121221 |
4 | 103303232231331031303 |
5 | 134300231430041123 |
6 | 2521200002525511 |
7 | 200226111646666 |
oct | 23635655751563 |
9 | 4733471526557 |
10 | 1361214690163 |
11 | 485319229a19 |
12 | 19b990066897 |
13 | 9b4923c03b3 |
14 | 49c514b36dd |
15 | 2561d11625d |
hex | 13ceeb7d373 |
1361214690163 has 2 divisors, whose sum is σ = 1361214690164. Its totient is φ = 1361214690162.
The previous prime is 1361214690161. The next prime is 1361214690263. The reversal of 1361214690163 is 3610964121631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1361214690163 - 21 = 1361214690161 is a prime.
Together with 1361214690161, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1361214690161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680607345081 + 680607345082.
It is an arithmetic number, because the mean of its divisors is an integer number (680607345082).
Almost surely, 21361214690163 is an apocalyptic number.
1361214690163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361214690163 is an equidigital number, since it uses as much as digits as its factorization.
1361214690163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 43.
It can be divided in two parts, 136121 and 4690163, that added together give a palindrome (4826284).
The spelling of 1361214690163 in words is "one trillion, three hundred sixty-one billion, two hundred fourteen million, six hundred ninety thousand, one hundred sixty-three".
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