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1361254173089 is a prime number
BaseRepresentation
bin10011110011110001000…
…100100100100110100001
311211010122010212212000112
4103303301010210212201
5134300322032014324
62521203533101105
7200230101362366
oct23636104444641
94733563785015
101361254173089
11485339547038
1219b9a1327795
139b49a635785
1449c5683046d
1525621814c0e
hex13cf11249a1

1361254173089 has 2 divisors, whose sum is σ = 1361254173090. Its totient is φ = 1361254173088.

The previous prime is 1361254173049. The next prime is 1361254173107. The reversal of 1361254173089 is 9803714521631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1288349853025 + 72904320064 = 1135055^2 + 270008^2 .

It is a cyclic number.

It is not a de Polignac number, because 1361254173089 - 28 = 1361254172833 is a prime.

It is not a weakly prime, because it can be changed into another prime (1361254173049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680627086544 + 680627086545.

It is an arithmetic number, because the mean of its divisors is an integer number (680627086545).

It is a 1-persistent number, because it is pandigital, but 2⋅1361254173089 = 2722508346178 is not.

Almost surely, 21361254173089 is an apocalyptic number.

It is an amenable number.

1361254173089 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361254173089 is an equidigital number, since it uses as much as digits as its factorization.

1361254173089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 50.

The spelling of 1361254173089 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-four million, one hundred seventy-three thousand, eighty-nine".