Base | Representation |
---|---|
bin | 10011110011110001000… |
… | …100100100100110100001 |
3 | 11211010122010212212000112 |
4 | 103303301010210212201 |
5 | 134300322032014324 |
6 | 2521203533101105 |
7 | 200230101362366 |
oct | 23636104444641 |
9 | 4733563785015 |
10 | 1361254173089 |
11 | 485339547038 |
12 | 19b9a1327795 |
13 | 9b49a635785 |
14 | 49c5683046d |
15 | 25621814c0e |
hex | 13cf11249a1 |
1361254173089 has 2 divisors, whose sum is σ = 1361254173090. Its totient is φ = 1361254173088.
The previous prime is 1361254173049. The next prime is 1361254173107. The reversal of 1361254173089 is 9803714521631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1288349853025 + 72904320064 = 1135055^2 + 270008^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361254173089 - 28 = 1361254172833 is a prime.
It is not a weakly prime, because it can be changed into another prime (1361254173049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680627086544 + 680627086545.
It is an arithmetic number, because the mean of its divisors is an integer number (680627086545).
It is a 1-persistent number, because it is pandigital, but 2⋅1361254173089 = 2722508346178 is not.
Almost surely, 21361254173089 is an apocalyptic number.
It is an amenable number.
1361254173089 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361254173089 is an equidigital number, since it uses as much as digits as its factorization.
1361254173089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 1361254173089 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-four million, one hundred seventy-three thousand, eighty-nine".
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