Base | Representation |
---|---|
bin | 10011110011110001000… |
… | …100100100100110110011 |
3 | 11211010122010212212001012 |
4 | 103303301010210212303 |
5 | 134300322032014412 |
6 | 2521203533101135 |
7 | 200230101362423 |
oct | 23636104444663 |
9 | 4733563785035 |
10 | 1361254173107 |
11 | 485339547054 |
12 | 19b9a13277ab |
13 | 9b49a63579a |
14 | 49c56830483 |
15 | 25621814c22 |
hex | 13cf11249b3 |
1361254173107 has 2 divisors, whose sum is σ = 1361254173108. Its totient is φ = 1361254173106.
The previous prime is 1361254173089. The next prime is 1361254173131. The reversal of 1361254173107 is 7013714521631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1361254173107 - 220 = 1361253124531 is a prime.
It is not a weakly prime, because it can be changed into another prime (1361254173197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680627086553 + 680627086554.
It is an arithmetic number, because the mean of its divisors is an integer number (680627086554).
Almost surely, 21361254173107 is an apocalyptic number.
1361254173107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361254173107 is an equidigital number, since it uses as much as digits as its factorization.
1361254173107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 105840, while the sum is 41.
Adding to 1361254173107 its reverse (7013714521631), we get a palindrome (8374968694738).
The spelling of 1361254173107 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-four million, one hundred seventy-three thousand, one hundred seven".
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