Base | Representation |
---|---|
bin | 10011110011110001000… |
… | …101111001010011100001 |
3 | 11211010122011112110221022 |
4 | 103303301011321103201 |
5 | 134300322124120113 |
6 | 2521203544335225 |
7 | 200230104336032 |
oct | 23636105712341 |
9 | 4733564473838 |
10 | 1361254520033 |
11 | 485339763771 |
12 | 19b9a1474515 |
13 | 9b49a727675 |
14 | 49c568c0a89 |
15 | 25621882908 |
hex | 13cf11794e1 |
1361254520033 has 2 divisors, whose sum is σ = 1361254520034. Its totient is φ = 1361254520032.
The previous prime is 1361254520027. The next prime is 1361254520047. The reversal of 1361254520033 is 3300254521631.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 942157539904 + 419096980129 = 970648^2 + 647377^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361254520033 - 238 = 1086376613089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1361254519975 and 1361254520002.
It is not a weakly prime, because it can be changed into another prime (1361251520033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680627260016 + 680627260017.
It is an arithmetic number, because the mean of its divisors is an integer number (680627260017).
Almost surely, 21361254520033 is an apocalyptic number.
It is an amenable number.
1361254520033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361254520033 is an equidigital number, since it uses as much as digits as its factorization.
1361254520033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 1361254520033 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-four million, five hundred twenty thousand, thirty-three".
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