Base | Representation |
---|---|
bin | 10011110011110100110… |
… | …010000111001001110101 |
3 | 11211010210111001110220221 |
4 | 103303310302013021311 |
5 | 134300434002131431 |
6 | 2521214035454341 |
7 | 200231455561513 |
oct | 23636462071165 |
9 | 4733714043827 |
10 | 1361316442741 |
11 | 485370708162 |
12 | 19b9ba1573b1 |
13 | 9b4aa4c8818 |
14 | 49c60bdd4b3 |
15 | 25627015111 |
hex | 13cf4c87275 |
1361316442741 has 2 divisors, whose sum is σ = 1361316442742. Its totient is φ = 1361316442740.
The previous prime is 1361316442691. The next prime is 1361316442763. The reversal of 1361316442741 is 1472446131631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1357583843716 + 3732599025 = 1165154^2 + 61095^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361316442741 - 213 = 1361316434549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361316442441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680658221370 + 680658221371.
It is an arithmetic number, because the mean of its divisors is an integer number (680658221371).
Almost surely, 21361316442741 is an apocalyptic number.
It is an amenable number.
1361316442741 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361316442741 is an equidigital number, since it uses as much as digits as its factorization.
1361316442741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 290304, while the sum is 43.
The spelling of 1361316442741 in words is "one trillion, three hundred sixty-one billion, three hundred sixteen million, four hundred forty-two thousand, seven hundred forty-one".
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