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1361316443233 is a prime number
BaseRepresentation
bin10011110011110100110…
…010000111010001100001
311211010210111001111121011
4103303310302013101201
5134300434002140413
62521214035500521
7200231455563115
oct23636462072141
94733714044534
101361316443233
1148537070856a
1219b9ba157741
139b4aa4c8b06
1449c60bdd745
152562701533d
hex13cf4c87461

1361316443233 has 2 divisors, whose sum is σ = 1361316443234. Its totient is φ = 1361316443232.

The previous prime is 1361316443209. The next prime is 1361316443257. The reversal of 1361316443233 is 3323446131631.

It is a balanced prime because it is at equal distance from previous prime (1361316443209) and next prime (1361316443257).

It can be written as a sum of positive squares in only one way, i.e., 1164169787089 + 197146656144 = 1078967^2 + 444012^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1361316443233 is a prime.

It is a super-2 number, since 2×13613164432332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1361316443203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680658221616 + 680658221617.

It is an arithmetic number, because the mean of its divisors is an integer number (680658221617).

Almost surely, 21361316443233 is an apocalyptic number.

It is an amenable number.

1361316443233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361316443233 is an equidigital number, since it uses as much as digits as its factorization.

1361316443233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 279936, while the sum is 40.

The spelling of 1361316443233 in words is "one trillion, three hundred sixty-one billion, three hundred sixteen million, four hundred forty-three thousand, two hundred thirty-three".