Base | Representation |
---|---|
bin | 10011110011110101000… |
… | …111010100010000101101 |
3 | 11211010210212111220001011 |
4 | 103303311013110100231 |
5 | 134300441413021303 |
6 | 2521214354545221 |
7 | 200231554042621 |
oct | 23636507242055 |
9 | 4733725456034 |
10 | 1361322001453 |
11 | 485373864537 |
12 | 19b9bbb98211 |
13 | 9b4ab6c39bb |
14 | 49c61849181 |
15 | 2562776216d |
hex | 13cf51d442d |
1361322001453 has 2 divisors, whose sum is σ = 1361322001454. Its totient is φ = 1361322001452.
The previous prime is 1361322001397. The next prime is 1361322001463. The reversal of 1361322001453 is 3541002231631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1014780213769 + 346541787684 = 1007363^2 + 588678^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361322001453 - 213 = 1361321993261 is a prime.
It is a super-3 number, since 3×13613220014533 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361322001463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680661000726 + 680661000727.
It is an arithmetic number, because the mean of its divisors is an integer number (680661000727).
Almost surely, 21361322001453 is an apocalyptic number.
It is an amenable number.
1361322001453 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361322001453 is an equidigital number, since it uses as much as digits as its factorization.
1361322001453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 1361322001453 in words is "one trillion, three hundred sixty-one billion, three hundred twenty-two million, one thousand, four hundred fifty-three".
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