1361326171237 has 2 divisors, whose sum is σ = 1361326171238. Its totient is φ = 1361326171236.

The previous prime is 1361326171213. The next prime is 1361326171273. The reversal of 1361326171237 is 7321716231631.

Together with next prime (1361326171273) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1044093632481 + 317232538756 = 1021809^2 + 563234^2 .

It is an emirp because it is prime and its reverse (7321716231631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1361326171237 is a prime.

It is a super-2 number, since 2×1361326171237² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1361326171193 and 1361326171202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1361326271237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680663085618 + 680663085619.

It is an arithmetic number, because the mean of its divisors is an integer number (680663085619).

Almost surely, 2^{1361326171237} is an apocalyptic number.

It is an amenable number.

1361326171237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361326171237 is an equidigital number, since it uses as much as digits as its factorization.

1361326171237 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 190512, while the sum is 43.

The spelling of 1361326171237 in words is "one trillion, three hundred sixty-one billion, three hundred twenty-six million, one hundred seventy-one thousand, two hundred thirty-seven".