Base | Representation |
---|---|
bin | 10011110011110101011… |
… | …000011000010000111111 |
3 | 11211010211011221010122021 |
4 | 103303311120120100333 |
5 | 134300444034134203 |
6 | 2521215034501011 |
7 | 200231640052165 |
oct | 23636530302077 |
9 | 4733734833567 |
10 | 1361326474303 |
11 | 48537633a004 |
12 | 19ba01594767 |
13 | 9b4ac5cb863 |
14 | 49c62291235 |
15 | 25627d475bd |
hex | 13cf561843f |
1361326474303 has 2 divisors, whose sum is σ = 1361326474304. Its totient is φ = 1361326474302.
The previous prime is 1361326474247. The next prime is 1361326474327. The reversal of 1361326474303 is 3034746231631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361326474303 - 29 = 1361326473791 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1361326474303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361326474373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680663237151 + 680663237152.
It is an arithmetic number, because the mean of its divisors is an integer number (680663237152).
Almost surely, 21361326474303 is an apocalyptic number.
1361326474303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361326474303 is an equidigital number, since it uses as much as digits as its factorization.
1361326474303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 43.
The spelling of 1361326474303 in words is "one trillion, three hundred sixty-one billion, three hundred twenty-six million, four hundred seventy-four thousand, three hundred three".
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