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136148208701 is a prime number
BaseRepresentation
bin111111011001100010…
…0001100110000111101
3111000102101212121102012
41332303010030300331
54212312420134301
6142313504341005
712556610452031
oct1766304146075
9430371777365
10136148208701
115281612934a
1222477914765
13cab989304b
146837c581c1
15381c9c4ebb
hex1fb310cc3d

136148208701 has 2 divisors, whose sum is σ = 136148208702. Its totient is φ = 136148208700.

The previous prime is 136148208671. The next prime is 136148208727. The reversal of 136148208701 is 107802841631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132907639225 + 3240569476 = 364565^2 + 56926^2 .

It is an emirp because it is prime and its reverse (107802841631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136148208701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136148208761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68074104350 + 68074104351.

It is an arithmetic number, because the mean of its divisors is an integer number (68074104351).

Almost surely, 2136148208701 is an apocalyptic number.

It is an amenable number.

136148208701 is a deficient number, since it is larger than the sum of its proper divisors (1).

136148208701 is an equidigital number, since it uses as much as digits as its factorization.

136148208701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 41.

The spelling of 136148208701 in words is "one hundred thirty-six billion, one hundred forty-eight million, two hundred eight thousand, seven hundred one".