Base | Representation |
---|---|
bin | 10011110011111111101… |
… | …101101010001111001001 |
3 | 11211011021021010021020001 |
4 | 103303333231222033021 |
5 | 134301322423400342 |
6 | 2521244150203001 |
7 | 200236143365116 |
oct | 23637755521711 |
9 | 4734237107201 |
10 | 1361499825097 |
11 | 485455180025 |
12 | 19ba4b653461 |
13 | 9b5094b50a9 |
14 | 49c7b2d790d |
15 | 2563818a8b7 |
hex | 13cffb6a3c9 |
1361499825097 has 2 divisors, whose sum is σ = 1361499825098. Its totient is φ = 1361499825096.
The previous prime is 1361499825031. The next prime is 1361499825109. The reversal of 1361499825097 is 7905289941631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1221944533056 + 139555292041 = 1105416^2 + 373571^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361499825097 - 27 = 1361499824969 is a prime.
It is not a weakly prime, because it can be changed into another prime (1361491825097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680749912548 + 680749912549.
It is an arithmetic number, because the mean of its divisors is an integer number (680749912549).
It is a 1-persistent number, because it is pandigital, but 2⋅1361499825097 = 2722999650194 is not.
Almost surely, 21361499825097 is an apocalyptic number.
It is an amenable number.
1361499825097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361499825097 is an equidigital number, since it uses as much as digits as its factorization.
1361499825097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29393280, while the sum is 64.
The spelling of 1361499825097 in words is "one trillion, three hundred sixty-one billion, four hundred ninety-nine million, eight hundred twenty-five thousand, ninety-seven".
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