Base | Representation |
---|---|
bin | 10011110100001111000… |
… | …011100001011011111111 |
3 | 11211011221012110000001112 |
4 | 103310033003201123333 |
5 | 134302334321330323 |
6 | 2521325503032235 |
7 | 200245420224332 |
oct | 23641703413377 |
9 | 4734835400045 |
10 | 1361757214463 |
11 | 4855774a0508 |
12 | 19bb0189b67b |
13 | 9b54a913ca9 |
14 | 49ca3578619 |
15 | 25650a7e178 |
hex | 13d0f0e16ff |
1361757214463 has 2 divisors, whose sum is σ = 1361757214464. Its totient is φ = 1361757214462.
The previous prime is 1361757214423. The next prime is 1361757214487. The reversal of 1361757214463 is 3644127571631.
It is a strong prime.
It is an emirp because it is prime and its reverse (3644127571631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1361757214463 - 226 = 1361690105599 is a prime.
It is a super-2 number, since 2×13617572144632 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361757214423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680878607231 + 680878607232.
It is an arithmetic number, because the mean of its divisors is an integer number (680878607232).
Almost surely, 21361757214463 is an apocalyptic number.
1361757214463 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361757214463 is an equidigital number, since it uses as much as digits as its factorization.
1361757214463 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2540160, while the sum is 50.
The spelling of 1361757214463 in words is "one trillion, three hundred sixty-one billion, seven hundred fifty-seven million, two hundred fourteen thousand, four hundred sixty-three".
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