Base | Representation |
---|---|
bin | 10011110100010001010… |
… | …110000111000011101011 |
3 | 11211012000212202022011001 |
4 | 103310101112013003223 |
5 | 134302424141012304 |
6 | 2521333354415431 |
7 | 200246364651622 |
oct | 23642126070353 |
9 | 4735025668131 |
10 | 1361795641579 |
11 | 48559715735a |
12 | 19bb12731577 |
13 | 9b555879929 |
14 | 49ca86dc6b9 |
15 | 2565411eda4 |
hex | 13d115870eb |
1361795641579 has 2 divisors, whose sum is σ = 1361795641580. Its totient is φ = 1361795641578.
The previous prime is 1361795641489. The next prime is 1361795641603. The reversal of 1361795641579 is 9751465971631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361795641579 - 211 = 1361795639531 is a prime.
It is a super-2 number, since 2×13617956415792 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1361795641579.
It is not a weakly prime, because it can be changed into another prime (1361795641079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680897820789 + 680897820790.
It is an arithmetic number, because the mean of its divisors is an integer number (680897820790).
Almost surely, 21361795641579 is an apocalyptic number.
1361795641579 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361795641579 is an equidigital number, since it uses as much as digits as its factorization.
1361795641579 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42865200, while the sum is 64.
It can be divided in two parts, 13617 and 95641579, that added together give a triangular number (95655196 = T13831).
The spelling of 1361795641579 in words is "one trillion, three hundred sixty-one billion, seven hundred ninety-five million, six hundred forty-one thousand, five hundred seventy-nine".
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