Base | Representation |
---|---|
bin | 11001010111110001… |
… | …00010101101100111 |
3 | 1022011021120211102111 |
4 | 30223320202231213 |
5 | 210344003110143 |
6 | 10131340221451 |
7 | 661354550215 |
oct | 145370425547 |
9 | 38137524374 |
10 | 13621144423 |
11 | 585a865457 |
12 | 278183a887 |
13 | 1390c91893 |
14 | 933057cb5 |
15 | 54ac4999d |
hex | 32be22b67 |
13621144423 has 2 divisors, whose sum is σ = 13621144424. Its totient is φ = 13621144422.
The previous prime is 13621144417. The next prime is 13621144469. The reversal of 13621144423 is 32444112631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13621144423 - 25 = 13621144391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13621144483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6810572211 + 6810572212.
It is an arithmetic number, because the mean of its divisors is an integer number (6810572212).
Almost surely, 213621144423 is an apocalyptic number.
13621144423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13621144423 is an equidigital number, since it uses as much as digits as its factorization.
13621144423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13824, while the sum is 31.
The spelling of 13621144423 in words is "thirteen billion, six hundred twenty-one million, one hundred forty-four thousand, four hundred twenty-three".
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