Base | Representation |
---|---|
bin | 11001011000110010… |
… | …10101100110111001 |
3 | 1022011212202121101122 |
4 | 30230121111212321 |
5 | 210403203211442 |
6 | 10132244355025 |
7 | 661520614451 |
oct | 145431254671 |
9 | 38155677348 |
10 | 13629741497 |
11 | 58646a7579 |
12 | 27846a5a75 |
13 | 13929b19c8 |
14 | 934254d61 |
15 | 54b896dd2 |
hex | 32c6559b9 |
13629741497 has 2 divisors, whose sum is σ = 13629741498. Its totient is φ = 13629741496.
The previous prime is 13629741493. The next prime is 13629741617. The reversal of 13629741497 is 79414792631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7354091536 + 6275649961 = 85756^2 + 79219^2 .
It is a cyclic number.
It is not a de Polignac number, because 13629741497 - 22 = 13629741493 is a prime.
It is a super-3 number, since 3×136297414973 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13629741493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6814870748 + 6814870749.
It is an arithmetic number, because the mean of its divisors is an integer number (6814870749).
Almost surely, 213629741497 is an apocalyptic number.
It is an amenable number.
13629741497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13629741497 is an equidigital number, since it uses as much as digits as its factorization.
13629741497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2286144, while the sum is 53.
The spelling of 13629741497 in words is "thirteen billion, six hundred twenty-nine million, seven hundred forty-one thousand, four hundred ninety-seven".
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