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13631150023147 is a prime number
BaseRepresentation
bin1100011001011011111111…
…0110101110000111101011
31210021010101021121201022201
43012112333312232013223
53241313043401220042
644554021444001031
72604550414313416
oct306267766560753
953233337551281
1013631150023147
114385a35908778
121641984690177
1377b548024487
14351a73354b7d
1518989e0961b7
hexc65bfdae1eb

13631150023147 has 2 divisors, whose sum is σ = 13631150023148. Its totient is φ = 13631150023146.

The previous prime is 13631150023123. The next prime is 13631150023171. The reversal of 13631150023147 is 74132005113631.

It is a balanced prime because it is at equal distance from previous prime (13631150023123) and next prime (13631150023171).

It is an emirp because it is prime and its reverse (74132005113631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13631150023147 - 219 = 13631149498859 is a prime.

It is not a weakly prime, because it can be changed into another prime (13631150023747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6815575011573 + 6815575011574.

It is an arithmetic number, because the mean of its divisors is an integer number (6815575011574).

Almost surely, 213631150023147 is an apocalyptic number.

13631150023147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13631150023147 is an equidigital number, since it uses as much as digits as its factorization.

13631150023147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45360, while the sum is 37.

Adding to 13631150023147 its reverse (74132005113631), we get a palindrome (87763155136778).

The spelling of 13631150023147 in words is "thirteen trillion, six hundred thirty-one billion, one hundred fifty million, twenty-three thousand, one hundred forty-seven".