13633304420130 has 16 divisors (see below), whose sum is σ = 32719930608384. Its totient is φ = 3635547845360.

The previous prime is 13633304420011. The next prime is 13633304420137. The reversal of 13633304420130 is 3102440333631.

It is a junction number, because it is equal to n+sod(n) for n = 13633304420091 and 13633304420100.

It is not an unprimeable number, because it can be changed into a prime (13633304420137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227221740306 + ... + 227221740365.

It is an arithmetic number, because the mean of its divisors is an integer number (2044995663024).

Almost surely, 2^{13633304420130} is an apocalyptic number.

13633304420130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13633304420130 is an abundant number, since it is smaller than the sum of its proper divisors (19086626188254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13633304420130 is a wasteful number, since it uses less digits than its factorization.

13633304420130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 454443480681.

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 13633304420130 its reverse (3102440333631), we get a palindrome (16735744753761).

The spelling of 13633304420130 in words is "thirteen trillion, six hundred thirty-three billion, three hundred four million, four hundred twenty thousand, one hundred thirty".