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13634389907 is a prime number
BaseRepresentation
bin11001011001010110…
…00100011110010011
31022012012111202210222
430230223010132103
5210410400434112
610132532143255
7661605254615
oct145453043623
938165452728
1013634389907
115867291a36
122786167b2b
13139394b748
14934b04db5
1554beb4372
hex32cac4793

13634389907 has 2 divisors, whose sum is σ = 13634389908. Its totient is φ = 13634389906.

The previous prime is 13634389891. The next prime is 13634389939. The reversal of 13634389907 is 70998343631.

13634389907 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (70998343631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13634389907 - 24 = 13634389891 is a prime.

It is a super-2 number, since 2×136343899072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13634389007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6817194953 + 6817194954.

It is an arithmetic number, because the mean of its divisors is an integer number (6817194954).

Almost surely, 213634389907 is an apocalyptic number.

13634389907 is a deficient number, since it is larger than the sum of its proper divisors (1).

13634389907 is an equidigital number, since it uses as much as digits as its factorization.

13634389907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2939328, while the sum is 53.

The spelling of 13634389907 in words is "thirteen billion, six hundred thirty-four million, three hundred eighty-nine thousand, nine hundred seven".