Base | Representation |
---|---|
bin | 10011110101111000010… |
… | …101100001010111011011 |
3 | 11211100111022002122210021 |
4 | 103311320111201113123 |
5 | 134314444011243233 |
6 | 2522221041331311 |
7 | 200340245601631 |
oct | 23657025412733 |
9 | 4740438078707 |
10 | 1363523540443 |
11 | 4862a3545349 |
12 | 1a0315336b37 |
13 | 9b76c8439ac |
14 | 49dcdda7351 |
15 | 25705b84e2d |
hex | 13d785615db |
1363523540443 has 2 divisors, whose sum is σ = 1363523540444. Its totient is φ = 1363523540442.
The previous prime is 1363523540441. The next prime is 1363523540569. The reversal of 1363523540443 is 3440453253631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1363523540443 - 21 = 1363523540441 is a prime.
Together with 1363523540441, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1363523540443.
It is not a weakly prime, because it can be changed into another prime (1363523540441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681761770221 + 681761770222.
It is an arithmetic number, because the mean of its divisors is an integer number (681761770222).
Almost surely, 21363523540443 is an apocalyptic number.
1363523540443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1363523540443 is an equidigital number, since it uses as much as digits as its factorization.
1363523540443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1555200, while the sum is 43.
The spelling of 1363523540443 in words is "one trillion, three hundred sixty-three billion, five hundred twenty-three million, five hundred forty thousand, four hundred forty-three".
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