Base | Representation |
---|---|
bin | 11111000000001101101000… |
… | …011010101001011011111111 |
3 | 122212210022201011211110100121 |
4 | 133000031220122221123333 |
5 | 120333011123102441142 |
6 | 1202000110545235411 |
7 | 40502154115301443 |
oct | 3700155032513377 |
9 | 585708634743317 |
10 | 136354078562047 |
11 | 3a4a0492671a65 |
12 | 13362401032b67 |
13 | 5b11199480a08 |
14 | 2595803384823 |
15 | 10b6d38677c67 |
hex | 7c03686a96ff |
136354078562047 has 2 divisors, whose sum is σ = 136354078562048. Its totient is φ = 136354078562046.
The previous prime is 136354078561999. The next prime is 136354078562081. The reversal of 136354078562047 is 740265870453631.
It is a strong prime.
It is an emirp because it is prime and its reverse (740265870453631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136354078562047 - 219 = 136354078037759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136354078562147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68177039281023 + 68177039281024.
It is an arithmetic number, because the mean of its divisors is an integer number (68177039281024).
Almost surely, 2136354078562047 is an apocalyptic number.
136354078562047 is a deficient number, since it is larger than the sum of its proper divisors (1).
136354078562047 is an equidigital number, since it uses as much as digits as its factorization.
136354078562047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 101606400, while the sum is 61.
The spelling of 136354078562047 in words is "one hundred thirty-six trillion, three hundred fifty-four billion, seventy-eight million, five hundred sixty-two thousand, forty-seven".
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