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13637131610483 is a prime number
BaseRepresentation
bin1100011001110010010001…
…1000101010100101110011
31210021200211011000211120102
43012130210120222211303
53241412321143013413
645000451202103015
72605151556053513
oct306344430524563
953250734024512
1013637131610483
114388525302887
121642b7394aa6b
1377bc8c344474
1435207d92d843
15189aee293458
hexc672462a973

13637131610483 has 2 divisors, whose sum is σ = 13637131610484. Its totient is φ = 13637131610482.

The previous prime is 13637131610461. The next prime is 13637131610489. The reversal of 13637131610483 is 38401613173631.

It is a strong prime.

It is an emirp because it is prime and its reverse (38401613173631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13637131610483 - 230 = 13636057868659 is a prime.

It is a super-2 number, since 2×136371316104832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13637131610489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6818565805241 + 6818565805242.

It is an arithmetic number, because the mean of its divisors is an integer number (6818565805242).

Almost surely, 213637131610483 is an apocalyptic number.

13637131610483 is a deficient number, since it is larger than the sum of its proper divisors (1).

13637131610483 is an equidigital number, since it uses as much as digits as its factorization.

13637131610483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 653184, while the sum is 47.

The spelling of 13637131610483 in words is "thirteen trillion, six hundred thirty-seven billion, one hundred thirty-one million, six hundred ten thousand, four hundred eighty-three".