Base | Representation |
---|---|
bin | 11111000000101011100110… |
… | …011101100111110100001111 |
3 | 122212220101202211012102100011 |
4 | 133000223212131213310033 |
5 | 120334023024024322002 |
6 | 1202022552035214051 |
7 | 40504403421333562 |
oct | 3700534635476417 |
9 | 585811684172304 |
10 | 136386258042127 |
11 | 3a5030a609a6a5 |
12 | 133686a1a47327 |
13 | 5b142272414a2 |
14 | 25971b70484d9 |
15 | 10b7abd7b88d7 |
hex | 7c0ae6767d0f |
136386258042127 has 2 divisors, whose sum is σ = 136386258042128. Its totient is φ = 136386258042126.
The previous prime is 136386258042109. The next prime is 136386258042241. The reversal of 136386258042127 is 721240852683631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136386258042127 - 215 = 136386258009359 is a prime.
It is a super-2 number, since 2×1363862580421272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136386258042527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68193129021063 + 68193129021064.
It is an arithmetic number, because the mean of its divisors is an integer number (68193129021064).
Almost surely, 2136386258042127 is an apocalyptic number.
136386258042127 is a deficient number, since it is larger than the sum of its proper divisors (1).
136386258042127 is an equidigital number, since it uses as much as digits as its factorization.
136386258042127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23224320, while the sum is 58.
The spelling of 136386258042127 in words is "one hundred thirty-six trillion, three hundred eighty-six billion, two hundred fifty-eight million, forty-two thousand, one hundred twenty-seven".
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