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1363964830817 is a prime number
BaseRepresentation
bin10011110110010010101…
…000111010010001100001
311211101122001110112101012
4103312102220322101201
5134321344444041232
62522332523550305
7200354214524531
oct23662250722141
94741561415335
101363964830817
114864aa652336
121a041908b395
139b8100b1264
144a0328394c1
152572e7a29b2
hex13d92a3a461

1363964830817 has 2 divisors, whose sum is σ = 1363964830818. Its totient is φ = 1363964830816.

The previous prime is 1363964830799. The next prime is 1363964830819. The reversal of 1363964830817 is 7180384693631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 763589354896 + 600375475921 = 873836^2 + 774839^2 .

It is a cyclic number.

It is not a de Polignac number, because 1363964830817 - 220 = 1363963782241 is a prime.

Together with 1363964830819, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1363964830819) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681982415408 + 681982415409.

It is an arithmetic number, because the mean of its divisors is an integer number (681982415409).

Almost surely, 21363964830817 is an apocalyptic number.

It is an amenable number.

1363964830817 is a deficient number, since it is larger than the sum of its proper divisors (1).

1363964830817 is an equidigital number, since it uses as much as digits as its factorization.

1363964830817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15676416, while the sum is 59.

The spelling of 1363964830817 in words is "one trillion, three hundred sixty-three billion, nine hundred sixty-four million, eight hundred thirty thousand, eight hundred seventeen".