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13639679953 is a prime number
BaseRepresentation
bin11001011001111110…
…01111111111010001
31022012120110112101121
430230333033333101
5210413224224303
610133241402241
7662001236524
oct145477177721
938176415347
1013639679953
11586a275479
122787a99381
131394a81553
149356c0bbb
1554c6ab9bd
hex32cfcffd1

13639679953 has 2 divisors, whose sum is σ = 13639679954. Its totient is φ = 13639679952.

The previous prime is 13639679951. The next prime is 13639680053. The reversal of 13639679953 is 35997693631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11438944209 + 2200735744 = 106953^2 + 46912^2 .

It is an emirp because it is prime and its reverse (35997693631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13639679953 - 21 = 13639679951 is a prime.

Together with 13639679951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13639679891 and 13639679900.

It is not a weakly prime, because it can be changed into another prime (13639679951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6819839976 + 6819839977.

It is an arithmetic number, because the mean of its divisors is an integer number (6819839977).

Almost surely, 213639679953 is an apocalyptic number.

It is an amenable number.

13639679953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13639679953 is an equidigital number, since it uses as much as digits as its factorization.

13639679953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24800580, while the sum is 61.

The spelling of 13639679953 in words is "thirteen billion, six hundred thirty-nine million, six hundred seventy-nine thousand, nine hundred fifty-three".