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136403955770113 is a prime number
BaseRepresentation
bin11111000000111100000101…
…010101000110001100000001
3122212222002110012121011010001
4133000330011111012030001
5120334320300134120423
61202035040123040001
740505601116464303
oct3700740525061401
9585862405534101
10136403955770113
113a50a657a96679
1213370000970001
135b15ab7959a95
142597db566d973
1510b82a7364cad
hex7c0f05546301

136403955770113 has 2 divisors, whose sum is σ = 136403955770114. Its totient is φ = 136403955770112.

The previous prime is 136403955770107. The next prime is 136403955770179. The reversal of 136403955770113 is 311077559304631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133799953899249 + 2604001870864 = 11567193^2 + 1613692^2 .

It is a cyclic number.

It is not a de Polignac number, because 136403955770113 - 217 = 136403955639041 is a prime.

It is not a weakly prime, because it can be changed into another prime (136403955770413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68201977885056 + 68201977885057.

It is an arithmetic number, because the mean of its divisors is an integer number (68201977885057).

Almost surely, 2136403955770113 is an apocalyptic number.

It is an amenable number.

136403955770113 is a deficient number, since it is larger than the sum of its proper divisors (1).

136403955770113 is an equidigital number, since it uses as much as digits as its factorization.

136403955770113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7144200, while the sum is 55.

The spelling of 136403955770113 in words is "one hundred thirty-six trillion, four hundred three billion, nine hundred fifty-five million, seven hundred seventy thousand, one hundred thirteen".