Base | Representation |
---|---|
bin | 11111000000111100000101… |
… | …010101000110001011111011 |
3 | 122212222002110012121011002211 |
4 | 133000330011111012023323 |
5 | 120334320300134120412 |
6 | 1202035040123035551 |
7 | 40505601116464264 |
oct | 3700740525061373 |
9 | 585862405534084 |
10 | 136403955770107 |
11 | 3a50a657a96673 |
12 | 1337000096bbb7 |
13 | 5b15ab7959a8c |
14 | 2597db566d96b |
15 | 10b82a7364ca7 |
hex | 7c0f055462fb |
136403955770107 has 2 divisors, whose sum is σ = 136403955770108. Its totient is φ = 136403955770106.
The previous prime is 136403955770101. The next prime is 136403955770113. The reversal of 136403955770107 is 701077559304631.
It is a balanced prime because it is at equal distance from previous prime (136403955770101) and next prime (136403955770113).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136403955770107 is a prime.
It is not a weakly prime, because it can be changed into another prime (136403955770101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68201977885053 + 68201977885054.
It is an arithmetic number, because the mean of its divisors is an integer number (68201977885054).
Almost surely, 2136403955770107 is an apocalyptic number.
136403955770107 is a deficient number, since it is larger than the sum of its proper divisors (1).
136403955770107 is an equidigital number, since it uses as much as digits as its factorization.
136403955770107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16669800, while the sum is 58.
The spelling of 136403955770107 in words is "one hundred thirty-six trillion, four hundred three billion, nine hundred fifty-five million, seven hundred seventy thousand, one hundred seven".
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