Base | Representation |
---|---|
bin | 11111000000111110010111… |
… | …101000100101100101111111 |
3 | 122212222022210021022212212012 |
4 | 133000332113220211211333 |
5 | 120334340312022244043 |
6 | 1202040123445201435 |
7 | 40506016003213556 |
oct | 3700762750454577 |
9 | 585868707285765 |
10 | 136406410353023 |
11 | 3a5106a759a098 |
12 | 13370586a0027b |
13 | 5b160b9346ac5 |
14 | 259816965ad9d |
15 | 10b839cabda18 |
hex | 7c0f97a2597f |
136406410353023 has 2 divisors, whose sum is σ = 136406410353024. Its totient is φ = 136406410353022.
The previous prime is 136406410352983. The next prime is 136406410353043. The reversal of 136406410353023 is 320353014604631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136406410353023 - 214 = 136406410336639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136406410353043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68203205176511 + 68203205176512.
It is an arithmetic number, because the mean of its divisors is an integer number (68203205176512).
Almost surely, 2136406410353023 is an apocalyptic number.
136406410353023 is a deficient number, since it is larger than the sum of its proper divisors (1).
136406410353023 is an equidigital number, since it uses as much as digits as its factorization.
136406410353023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 41.
Adding to 136406410353023 its reverse (320353014604631), we get a palindrome (456759424957654).
The spelling of 136406410353023 in words is "one hundred thirty-six trillion, four hundred six billion, four hundred ten million, three hundred fifty-three thousand, twenty-three".
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