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136422500143 is a prime number
BaseRepresentation
bin111111100001101101…
…0100010011100101111
3111001010112000001112111
41333003122202130233
54213343130001033
6142401023344451
712566451055366
oct1770332423457
9431115001474
10136422500143
1152946a43596
1222533752127
13cb3165c287
1468624587dd
153836b067cd
hex1fc36a272f

136422500143 has 2 divisors, whose sum is σ = 136422500144. Its totient is φ = 136422500142.

The previous prime is 136422500131. The next prime is 136422500177. The reversal of 136422500143 is 341005224631.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 136422500143 - 225 = 136388945711 is a prime.

It is a super-3 number, since 3×1364225001433 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136422500183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211250071 + 68211250072.

It is an arithmetic number, because the mean of its divisors is an integer number (68211250072).

Almost surely, 2136422500143 is an apocalyptic number.

136422500143 is a deficient number, since it is larger than the sum of its proper divisors (1).

136422500143 is an equidigital number, since it uses as much as digits as its factorization.

136422500143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 136422500143 its reverse (341005224631), we get a palindrome (477427724774).

The spelling of 136422500143 in words is "one hundred thirty-six billion, four hundred twenty-two million, five hundred thousand, one hundred forty-three".