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136423415688173 is a prime number
BaseRepresentation
bin11111000001001110001101…
…001110110010101111101101
3122220000221200101212102012222
4133001032031032302233231
5120340130123404010143
61202052015120405125
740510160263165265
oct3701161516625755
9586027611772188
10136423415688173
113a517933672089
1213373931a767a5
135b178994876b3
142598cddd287a5
1510b8a4599b768
hex7c138d3b2bed

136423415688173 has 2 divisors, whose sum is σ = 136423415688174. Its totient is φ = 136423415688172.

The previous prime is 136423415688103. The next prime is 136423415688181. The reversal of 136423415688173 is 371886514324631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136361156954884 + 62258733289 = 11677378^2 + 249517^2 .

It is a cyclic number.

It is not a de Polignac number, because 136423415688173 - 212 = 136423415684077 is a prime.

It is a super-2 number, since 2×1364234156881732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136423415688103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211707844086 + 68211707844087.

It is an arithmetic number, because the mean of its divisors is an integer number (68211707844087).

Almost surely, 2136423415688173 is an apocalyptic number.

It is an amenable number.

136423415688173 is a deficient number, since it is larger than the sum of its proper divisors (1).

136423415688173 is an equidigital number, since it uses as much as digits as its factorization.

136423415688173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69672960, while the sum is 62.

The spelling of 136423415688173 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred fifteen million, six hundred eighty-eight thousand, one hundred seventy-three".