Base | Representation |
---|---|
bin | 11111000001001110001101… |
… | …101110110010010000011101 |
3 | 122220000221200222122111111002 |
4 | 133001032031232302100131 |
5 | 120340130133030343111 |
6 | 1202052020020240045 |
7 | 40510160424365114 |
oct | 3701161556622035 |
9 | 586027628574432 |
10 | 136423424074781 |
11 | 3a517938380068 |
12 | 13373934840025 |
13 | 5b1789b132a9c |
14 | 2598d010acc7b |
15 | 10b8a465a663b |
hex | 7c138dbb241d |
136423424074781 has 2 divisors, whose sum is σ = 136423424074782. Its totient is φ = 136423424074780.
The previous prime is 136423424074771. The next prime is 136423424074801. The reversal of 136423424074781 is 187470424324631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98457296179225 + 37966127895556 = 9922565^2 + 6161666^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136423424074781 is a prime.
It is a super-2 number, since 2×1364234240747812 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136423424074741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211712037390 + 68211712037391.
It is an arithmetic number, because the mean of its divisors is an integer number (68211712037391).
Almost surely, 2136423424074781 is an apocalyptic number.
It is an amenable number.
136423424074781 is a deficient number, since it is larger than the sum of its proper divisors (1).
136423424074781 is an equidigital number, since it uses as much as digits as its factorization.
136423424074781 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21676032, while the sum is 56.
The spelling of 136423424074781 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred twenty-four million, seventy-four thousand, seven hundred eighty-one".
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