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13644535452001 is a prime number
BaseRepresentation
bin1100011010001101110110…
…1100000101000101100001
31210022101221010122221202221
43012203131230011011201
53242023002033431001
645004114004111041
72605533210504346
oct306433554050541
953271833587687
1013644535452001
114390684606573
12164449b395481
1377c89c20538c
14352582d707cd
15189dd427e1a1
hexc68ddb05161

13644535452001 has 2 divisors, whose sum is σ = 13644535452002. Its totient is φ = 13644535452000.

The previous prime is 13644535451999. The next prime is 13644535452013. The reversal of 13644535452001 is 10025453544631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13424536930401 + 219998521600 = 3663951^2 + 469040^2 .

It is a cyclic number.

It is not a de Polignac number, because 13644535452001 - 21 = 13644535451999 is a prime.

Together with 13644535451999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13644535452091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822267726000 + 6822267726001.

It is an arithmetic number, because the mean of its divisors is an integer number (6822267726001).

Almost surely, 213644535452001 is an apocalyptic number.

It is an amenable number.

13644535452001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13644535452001 is an equidigital number, since it uses as much as digits as its factorization.

13644535452001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 13644535452001 its reverse (10025453544631), we get a palindrome (23669988996632).

The spelling of 13644535452001 in words is "thirteen trillion, six hundred forty-four billion, five hundred thirty-five million, four hundred fifty-two thousand, one".