Base | Representation |
---|---|
bin | 1100011010001101110110… |
… | …1100000101000101100001 |
3 | 1210022101221010122221202221 |
4 | 3012203131230011011201 |
5 | 3242023002033431001 |
6 | 45004114004111041 |
7 | 2605533210504346 |
oct | 306433554050541 |
9 | 53271833587687 |
10 | 13644535452001 |
11 | 4390684606573 |
12 | 164449b395481 |
13 | 77c89c20538c |
14 | 352582d707cd |
15 | 189dd427e1a1 |
hex | c68ddb05161 |
13644535452001 has 2 divisors, whose sum is σ = 13644535452002. Its totient is φ = 13644535452000.
The previous prime is 13644535451999. The next prime is 13644535452013. The reversal of 13644535452001 is 10025453544631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13424536930401 + 219998521600 = 3663951^2 + 469040^2 .
It is a cyclic number.
It is not a de Polignac number, because 13644535452001 - 21 = 13644535451999 is a prime.
Together with 13644535451999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13644535452091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822267726000 + 6822267726001.
It is an arithmetic number, because the mean of its divisors is an integer number (6822267726001).
Almost surely, 213644535452001 is an apocalyptic number.
It is an amenable number.
13644535452001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13644535452001 is an equidigital number, since it uses as much as digits as its factorization.
13644535452001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 13644535452001 its reverse (10025453544631), we get a palindrome (23669988996632).
The spelling of 13644535452001 in words is "thirteen trillion, six hundred forty-four billion, five hundred thirty-five million, four hundred fifty-two thousand, one".
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