Base | Representation |
---|---|
bin | 11111000001110011111001… |
… | …100101110011010001010111 |
3 | 122220011211011000100101220221 |
4 | 133001303321211303101113 |
5 | 120341311020410132011 |
6 | 1202122351142335211 |
7 | 40513122240232462 |
oct | 3701637145632127 |
9 | 586154130311827 |
10 | 136463888364631 |
11 | 3a533012414a23 |
12 | 1337b74812a507 |
13 | 5b1b649446369 |
14 | 259ac5d1b82d9 |
15 | 10b9b13c00971 |
hex | 7c1cf9973457 |
136463888364631 has 2 divisors, whose sum is σ = 136463888364632. Its totient is φ = 136463888364630.
The previous prime is 136463888364581. The next prime is 136463888364677.
136463888364631 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 136463888364631 - 211 = 136463888362583 is a prime.
It is a super-2 number, since 2×1364638883646312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136463888364431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68231944182315 + 68231944182316.
It is an arithmetic number, because the mean of its divisors is an integer number (68231944182316).
Almost surely, 2136463888364631 is an apocalyptic number.
136463888364631 is a deficient number, since it is larger than the sum of its proper divisors (1).
136463888364631 is an equidigital number, since it uses as much as digits as its factorization.
136463888364631 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 859963392, while the sum is 70.
The spelling of 136463888364631 in words is "one hundred thirty-six trillion, four hundred sixty-three billion, eight hundred eighty-eight million, three hundred sixty-four thousand, six hundred thirty-one".
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