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136494437 is a prime number
BaseRepresentation
bin10000010001010…
…11110101100101
3100111211122011112
420020223311211
5234420310222
621313314405
73245116652
oct1010536545
9314748145
10136494437
1170058322
1239865a05
1322380851
14141b0c29
15beb2be2
hex822bd65

136494437 has 2 divisors, whose sum is σ = 136494438. Its totient is φ = 136494436.

The previous prime is 136494433. The next prime is 136494497. The reversal of 136494437 is 734494631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130896481 + 5597956 = 11441^2 + 2366^2 .

It is a cyclic number.

It is not a de Polignac number, because 136494437 - 22 = 136494433 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 136494394 and 136494403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136494431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68247218 + 68247219.

It is an arithmetic number, because the mean of its divisors is an integer number (68247219).

Almost surely, 2136494437 is an apocalyptic number.

It is an amenable number.

136494437 is a deficient number, since it is larger than the sum of its proper divisors (1).

136494437 is an equidigital number, since it uses as much as digits as its factorization.

136494437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 217728, while the sum is 41.

The square root of 136494437 is about 11683.0833687002. The cubic root of 136494437 is about 514.8787687119.

The spelling of 136494437 in words is "one hundred thirty-six million, four hundred ninety-four thousand, four hundred thirty-seven".