Base | Representation |
---|---|
bin | 11001011011010010… |
… | …00011111000010011 |
3 | 1022020100002101022012 |
4 | 30231221003320103 |
5 | 210424030443103 |
6 | 10134312333135 |
7 | 662163346301 |
oct | 145551037023 |
9 | 38210071265 |
10 | 13650640403 |
11 | 58754811a4 |
12 | 278b6a41ab |
13 | 139711b31a |
14 | 936d35271 |
15 | 54d6242d8 |
hex | 32da43e13 |
13650640403 has 2 divisors, whose sum is σ = 13650640404. Its totient is φ = 13650640402.
The previous prime is 13650640391. The next prime is 13650640429. The reversal of 13650640403 is 30404605631.
13650640403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13650640403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13650640403.
It is not a weakly prime, because it can be changed into another prime (13650643403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6825320201 + 6825320202.
It is an arithmetic number, because the mean of its divisors is an integer number (6825320202).
Almost surely, 213650640403 is an apocalyptic number.
13650640403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13650640403 is an equidigital number, since it uses as much as digits as its factorization.
13650640403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 32.
The spelling of 13650640403 in words is "thirteen billion, six hundred fifty million, six hundred forty thousand, four hundred three".
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