Base | Representation |
---|---|
bin | 111111100100010100… |
… | …1110000101001101101 |
3 | 111001100122100122022111 |
4 | 1333020221300221231 |
5 | 4214033124022212 |
6 | 142413443044021 |
7 | 12601566025012 |
oct | 1771051605155 |
9 | 431318318274 |
10 | 136510376557 |
11 | 52991604425 |
12 | 22559070611 |
13 | cb46919759 |
14 | 686ddb1709 |
15 | 383e6b3ea7 |
hex | 1fc8a70a6d |
136510376557 has 2 divisors, whose sum is σ = 136510376558. Its totient is φ = 136510376556.
The previous prime is 136510376551. The next prime is 136510376573. The reversal of 136510376557 is 755673015631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98112406441 + 38397970116 = 313229^2 + 195954^2 .
It is a cyclic number.
It is not a de Polignac number, because 136510376557 - 223 = 136501987949 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136510376557.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136510376551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68255188278 + 68255188279.
It is an arithmetic number, because the mean of its divisors is an integer number (68255188279).
Almost surely, 2136510376557 is an apocalyptic number.
It is an amenable number.
136510376557 is a deficient number, since it is larger than the sum of its proper divisors (1).
136510376557 is an equidigital number, since it uses as much as digits as its factorization.
136510376557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1984500, while the sum is 49.
The spelling of 136510376557 in words is "one hundred thirty-six billion, five hundred ten million, three hundred seventy-six thousand, five hundred fifty-seven".
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