Base | Representation |
---|---|
bin | 10000010001100… |
… | …10001011110101 |
3 | 100111212221211111 |
4 | 20020302023311 |
5 | 234422123222 |
6 | 21314035021 |
7 | 3245255524 |
oct | 1010621365 |
9 | 314787744 |
10 | 136520437 |
11 | 70075909 |
12 | 39878a71 |
13 | 2238c631 |
14 | 141ba4bb |
15 | beba777 |
hex | 82322f5 |
136520437 has 2 divisors, whose sum is σ = 136520438. Its totient is φ = 136520436.
The previous prime is 136520401. The next prime is 136520443. The reversal of 136520437 is 734025631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134420836 + 2099601 = 11594^2 + 1449^2 .
It is a cyclic number.
It is not a de Polignac number, because 136520437 - 227 = 2302709 is a prime.
It is a super-3 number, since 3×1365204373 (a number of 25 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136520399 and 136520408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136520537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68260218 + 68260219.
It is an arithmetic number, because the mean of its divisors is an integer number (68260219).
Almost surely, 2136520437 is an apocalyptic number.
It is an amenable number.
136520437 is a deficient number, since it is larger than the sum of its proper divisors (1).
136520437 is an equidigital number, since it uses as much as digits as its factorization.
136520437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The square root of 136520437 is about 11684.1960356714. The cubic root of 136520437 is about 514.9114586842.
The spelling of 136520437 in words is "one hundred thirty-six million, five hundred twenty thousand, four hundred thirty-seven".
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