Base | Representation |
---|---|
bin | 111111100101111011… |
… | …0010100010111100111 |
3 | 111001111101021000011111 |
4 | 1333023312110113213 |
5 | 4214140341001411 |
6 | 142423040245451 |
7 | 12603116564161 |
oct | 1771366242747 |
9 | 431441230144 |
10 | 136564000231 |
11 | 52a098aa70a |
12 | 22573010887 |
13 | cb54a73339 |
14 | 687716d931 |
15 | 3844257721 |
hex | 1fcbd945e7 |
136564000231 has 2 divisors, whose sum is σ = 136564000232. Its totient is φ = 136564000230.
The previous prime is 136564000219. The next prime is 136564000247. The reversal of 136564000231 is 132000465631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136564000231 - 219 = 136563475943 is a prime.
It is a super-2 number, since 2×1365640002312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136564000193 and 136564000202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136564000271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68282000115 + 68282000116.
It is an arithmetic number, because the mean of its divisors is an integer number (68282000116).
Almost surely, 2136564000231 is an apocalyptic number.
136564000231 is a deficient number, since it is larger than the sum of its proper divisors (1).
136564000231 is an equidigital number, since it uses as much as digits as its factorization.
136564000231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 136564000231 its reverse (132000465631), we get a palindrome (268564465862).
The spelling of 136564000231 in words is "one hundred thirty-six billion, five hundred sixty-four million, two hundred thirty-one", and thus it is an aban number.
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