Base | Representation |
---|---|
bin | 111111100101111011… |
… | …0010111010000000001 |
3 | 111001111101021121100121 |
4 | 1333023312113100001 |
5 | 4214140341341113 |
6 | 142423040420241 |
7 | 12603116643451 |
oct | 1771366272001 |
9 | 431441247317 |
10 | 136564012033 |
11 | 52a09908569 |
12 | 22573017681 |
13 | cb54a78817 |
14 | 6877173d61 |
15 | 384425ae8d |
hex | 1fcbd97401 |
136564012033 has 2 divisors, whose sum is σ = 136564012034. Its totient is φ = 136564012032.
The previous prime is 136564012021. The next prime is 136564012037. The reversal of 136564012033 is 330210465631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88823073024 + 47740939009 = 298032^2 + 218497^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136564012033 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136564012033.
It is not a weakly prime, because it can be changed into another prime (136564012037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68282006016 + 68282006017.
It is an arithmetic number, because the mean of its divisors is an integer number (68282006017).
Almost surely, 2136564012033 is an apocalyptic number.
It is an amenable number.
136564012033 is a deficient number, since it is larger than the sum of its proper divisors (1).
136564012033 is an equidigital number, since it uses as much as digits as its factorization.
136564012033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 136564012033 its reverse (330210465631), we get a palindrome (466774477664).
The spelling of 136564012033 in words is "one hundred thirty-six billion, five hundred sixty-four million, twelve thousand, thirty-three".
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