Base | Representation |
---|---|
bin | 111111100110000000… |
… | …0000010111000010001 |
3 | 111001111120001112211121 |
4 | 1333030000002320101 |
5 | 4214142014100113 |
6 | 142423211042241 |
7 | 12603150344044 |
oct | 1771400027021 |
9 | 431446045747 |
10 | 136566550033 |
11 | 52a10291391 |
12 | 22573a40381 |
13 | cb55456ab4 |
14 | 6877634c5b |
15 | 38445ace8d |
hex | 1fcc002e11 |
136566550033 has 2 divisors, whose sum is σ = 136566550034. Its totient is φ = 136566550032.
The previous prime is 136566550031. The next prime is 136566550063. The reversal of 136566550033 is 330055665631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 132054472449 + 4512077584 = 363393^2 + 67172^2 .
It is a cyclic number.
It is not a de Polignac number, because 136566550033 - 21 = 136566550031 is a prime.
Together with 136566550031, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (136566550031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68283275016 + 68283275017.
It is an arithmetic number, because the mean of its divisors is an integer number (68283275017).
Almost surely, 2136566550033 is an apocalyptic number.
It is an amenable number.
136566550033 is a deficient number, since it is larger than the sum of its proper divisors (1).
136566550033 is an equidigital number, since it uses as much as digits as its factorization.
136566550033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729000, while the sum is 43.
The spelling of 136566550033 in words is "one hundred thirty-six billion, five hundred sixty-six million, five hundred fifty thousand, thirty-three".
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