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13662400597 is a prime number
BaseRepresentation
bin11001011100101011…
…11011000001010101
31022021011012212020221
430232111323001111
5210440033304342
610135412354341
7662365326466
oct145625730125
938234185227
1013662400597
11588108386a
1227936159b1
1313996a8111
14938716d6d
1554e698a67
hex32e57b055

13662400597 has 2 divisors, whose sum is σ = 13662400598. Its totient is φ = 13662400596.

The previous prime is 13662400573. The next prime is 13662400601. The reversal of 13662400597 is 79500426631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12496109796 + 1166290801 = 111786^2 + 34151^2 .

It is an emirp because it is prime and its reverse (79500426631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13662400597 - 27 = 13662400469 is a prime.

It is a super-2 number, since 2×136624005972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13662403597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831200298 + 6831200299.

It is an arithmetic number, because the mean of its divisors is an integer number (6831200299).

Almost surely, 213662400597 is an apocalyptic number.

It is an amenable number.

13662400597 is a deficient number, since it is larger than the sum of its proper divisors (1).

13662400597 is an equidigital number, since it uses as much as digits as its factorization.

13662400597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 43.

The spelling of 13662400597 in words is "thirteen billion, six hundred sixty-two million, four hundred thousand, five hundred ninety-seven".